1. Find the missing side length. Round your answer to the nearest tenth.6.7 21.3 5.5 43.22. Find the length of side a. Round to the nearest tenth.12 378.4 18.3 19.53. Find the length of side BA. Round to the nearest hundredth. 0.42 0.65 0.83 1.25

QUESTION 1We can use the cosine rule to find the missing side length.Recall that the cosine rule for a triangle with sides a,b,c and an included angle A is [tex]a^2=b^2+c^2-2bc\cos A[/tex]Let the missing side length in the triangle with sides 6, 9 and the included angle of [tex]37\degree[/tex] be [tex]a[/tex] units.We then substitute the values into the cosine rule to obtain;[tex]a^2=6^2+9^2-2(6)(9)\cos 37\degree[/tex][tex]a^2=36+81-108\cos 37\degree[/tex][tex]a^2=30.747[/tex][tex]\Rightarrow a=\sqrt{30.747}[/tex][tex]\Rightarrow a=\sqrt{30.747}[/tex][tex]\Rightarrow a=5.5[/tex] units to the nearest tenth.QUESTION 2We again use the cosine rule: [tex]a^2=b^2+c^2-2bc\cos A[/tex]We substitute the given values to obtain;[tex]a^2=11^2+13^2-2(11)(13)\cos 108\degree[/tex][tex]a^2=121+169-286\cos 108\degree[/tex][tex]a^2=378.379[/tex][tex]\Rightarrow a=\sqrt{378.379}[/tex][tex]\Rightarrow a=19.5[/tex] to the nearest tenthQUESTION 3We again use the cosine rule : [tex]|BA|^2=(\frac{1}{2})^2+(\frac{1}{3})^2-2(\frac{1}{2})(\frac{1}{3})\cos 100\degree[/tex][tex]|BA|^2=0.418899[/tex][tex]|BA|=\sqrt{0.418899}[/tex][tex]|BA|=0.65[/tex] to the nearest hundredth