MATH SOLVE

2 months ago

Q:
# What is the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is y=5/4xβ2 ?

Accepted Solution

A:

Answer:[tex]\displaystyle 4x + 5y = 65\:or\:y = -\frac{4}{5}x + 13[/tex]Step-by-step explanation:5 = ββ
[10] + b β8[tex]\displaystyle 13 = b \\ \\ y = -\frac{4}{5}x + 13[/tex]If you want it in Standard Form: y = ββ
x + 13+ β
x + β
x___________β
x + y = 13 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]5[β
x + y = 13][tex]\displaystyle 4x + 5y = 65[/tex]* Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES], so 1ΒΌ [or 5β4] becomes ββ
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