MATH SOLVE

2 months ago

Q:
# The table of values represents a polynomial function f(x).How much greater is the average rate of change over the interval [7, 9] than the interval [4, 6] ?

Accepted Solution

A:

average rate = (f(final)-f(initial))/(x(final)-x(initial))

the interval [7, 9]

av. rate =(3878-1852)/(9-7)=1013

the interval [4, 6]

av. rate =(1178-358)/(6-4)=410

1013-410=603 greater the average rate of change over the interval [7, 9] than the interval [4, 6]

the interval [7, 9]

av. rate =(3878-1852)/(9-7)=1013

the interval [4, 6]

av. rate =(1178-358)/(6-4)=410

1013-410=603 greater the average rate of change over the interval [7, 9] than the interval [4, 6]