The table of values represents a polynomial function f(x).How much greater is the average rate of change over the interval [7, 9] than the interval [4, 6] ?
Accepted Solution
A:
average rate = (f(final)-f(initial))/(x(final)-x(initial)) the interval [7, 9] av. rate =(3878-1852)/(9-7)=1013 the interval [4, 6] av. rate =(1178-358)/(6-4)=410 1013-410=603 greater the average rate of change over the interval [7, 9] than the interval [4, 6]